Breaking the Code
Garrybl on 08/30/2006
|Everyone familiar with codes knows how to use a simple letter-number substitution, A-1, B-2, etc. and so on through to I-9. This quiz will use that set of rules, but add in quite a few additional complexities, the first of which is three additional counting letters; N-14, R-18, T-20. The presence of any other letter will make a word-total zero.|
So ACE = 9, (1+3+5) TART = 59 (20+1+18+20).
Additionally when we add up the score of words, starting from left and going through to the right, we add one further little complexity: any time a word has two consecutive letters of the alphabet in the correct order it will be treated as a two-digit number, with a consecutive set of three letters representing the appropriate three-digit number. But a set in reverse order will be a minus number. Thus HIDE is 134 (89 + 45) HIED is 35 (89-54) and DEFER is 479 (456 + 5 + 18). N, R, and T can obviously never be consecutive to any other letter.
Get it, got it, good! All you need to do is add up the ten words that follow.
(The picture is Alan Turing -- inventor of the modern computer and hero of breaking the code, though Enigma is rather harder than mine!)
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